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0.04x^2-2.7x+2=0
a = 0.04; b = -2.7; c = +2;
Δ = b2-4ac
Δ = -2.72-4·0.04·2
Δ = 6.97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.7)-\sqrt{6.97}}{2*0.04}=\frac{2.7-\sqrt{6.97}}{0.08} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.7)+\sqrt{6.97}}{2*0.04}=\frac{2.7+\sqrt{6.97}}{0.08} $
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